Q:

Television viewing reached a new high when the Nielsen Company reported a mean daily viewing time of 8.35 hours per household (USA Today, November 11, 2009). Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household.A) What is the probability that a household views television between 5 and 10 hours a day?B) How many hours of television viewing must a household have in order to be in the top 3% of all television viewing households?C) What is the probability that a household views television more than 3 hours a day?

Accepted Solution

A:
Answer:Probability of viewing television between 5 to 10 hr is Β 0.6553Step-by-step explanation:Given data:total time period of viewing of per household = 8.35 hrstandard deviation = 2.5 hrProbability between 5 to 10 hr can be obtained as= P(Between 5 and 10 hours)[tex]= P(\frac{(5 - 8.35)}{2.5} < z < \frac{(10 - 8.35)}{2.5})[/tex]= P(-1.34 < z < 0.66)= P(z < 0.66) - P(z < -1.34)determine z value from standard z table= 0.7454 - 0.0901= 0.6553